00:16
The problem discussed is about finding out the minimum number of days to make M number of bouquets from flowers blooming on different days.
00:39
Explanation of how the array Bloomday contains the blooming days for n flowers, with each index representing a different flower and its blooming day.
01:01
The goal is to make two bouquets by picking three adjacent bloomed flowers for each bouquet after a certain number of days.
01:29
If you're on the 13th day, all flowers considered in the example would have bloomed, and it would be possible to make the necessary bouquets.
02:32
It is determined that on the 7th day, it would not be possible to make enough bouquets since not all required flowers are bloomed and adjacent.
03:35
On the 11th day, it is still not possible to make enough bouquets due to the blooming pattern of the flowers.
04:02
The day before which it is impossible to make the bouquets is identified, concluding that any day less than the 11th day would not work.
04:28
Since the 12th day allows enough flowers to bloom to make the required bouquets, the minimum number of days required is deduced to be 12.
04:46
An alternative example is provided, demonstrating a case where it would be impossible to form enough bouquets even if all flowers are bloomed.
05:18
Explanation of when to return -1 for impossible situations where enough bouquets cannot be formed.
05:28
First approach to solve the problem is discussed, focusing on identifying the impossible case.
06:02
Concept explained that if the total number of bouquets that need to be formed times the number of adjacent flowers required is greater than the number of available bloomed flowers, it is impossible to make the bouquets.
07:55
Introduction to the next step, which includes considering the maximum possible answer based on the maximum number given in the Bloomday array.
08:11
Discussion on how to find the minimum possible answer, which involves checking the blooming day by day.
09:01
A function is written to check if it is possible to form enough bouquets on a given day.
10:16
The process of finding the minimum possible day is explained, where you continue to check each day until you find a day where enough bouquets can be made.
12:13
Implementation of checking how many bouquets can be made based on the day is discussed, with a counter to track.
13:01
Written code is discussed to determine the possibility of forming the required number of bouquets with a given blooming day array.
15:11
At the end of the loop, ensure to check if there's an opportunity to form another bouquet with the remaining bloomed flowers.
15:21
The function to determine if it is possible to make the required bouquets is completed.
16:01
Introduction to the brute force approach to solve the problem, iterating from the minimum to the maximum day.
17:00
Time complexity for the brute force approach is determined to be the range of days (max minus min) times the array size n.
17:37
Discussion on how to optimize the brute force approach using binary search by identifying the possible and impossible ranges for the bouquets to be formed.
19:03
The binary search process is explained step by step using the provided example, starting with the midpoint and adjusting the range based on what's possible.
21:53
The explanation of the binary search is concluded, with the answer being determined where the low pointer ends up after repeated elimination of ranges.
22:01
The final time complexity for the optimized binary search approach is determined as O(n log(max-min+1)).
22:04
It is mentioned that no extra space is used in the optimized solution.
22:06
Closing of the video where the optimization of the approach using binary search is emphasized.
